Published by:
CGP EDU Academic Team
Published on: September 12, 2026
A body of mass 2 kg is thrown up vertically with K.E. of 490 joules. If the acceleration due to gravity is 9.8m/s 2 , then the height at which the K.E. of the body becomes half its original value is given by
Text Solution
Verified by ExpertsThe correct answer is:
B
Let h is that height at which the kinetic energy of the body becomes half its original value i.e. half of its kinetic energy will convert into potential energy
$\therefore mgh = \frac{490}{2} \Rightarrow 2 \times 9.8 \times h = \frac{490}{2} \Rightarrow h = 12.5 \text{ m}.$
Prepare Smarter with CGP Edu
Get practice questions, solutions, and test series in one place.
Write a Review
Share your experience with this question and solution.
Commentary
Send your comment, doubt, correction, or feedback to admin.
Similar Questions
Explore conceptually related problems
A bomb of 12 kg explodes into two pieces of masses 4 kg and 8 kg. The velocity of 8kg mass is 6 m/s…
If the linear momentum is increased by 50%, the kinetic energy will increase by
A body of mass 2 kg is projected vertically upwards with a velocity of 2 m sec -1 . The K.E. of the…
Two bodies of different masses $n_1$ and $n_2$ have equal momenta. Their kinetic energies $E_1$ and…
If velocity of a body is twice of previous velocity, then kinetic energy will become
Two bodies of masses m and 2m have same momentum. Their respective kinetic energies E 1 and E 2 are…